Question

Oblicz moc wydzielona na oporniku R1 i R2

R1= 96Ω

R2= 48Ω

U=ε= 24 [V]

Answer 1

U=24V

R1=96Ω

R2=48Ω

P1=?

P2=?

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P=U*I

z prawa Ohma I=U/R stąd P=U²/R

P1=U²/R1=24²/96=6 [V²/Ω=V²/(V/A)=V²*A/V=V*A=W]

P2=U²/R2=24²/48=12W