Oblicz mase a) matalu b) tlenku metalu c) wodorotlenku potrzebną do otrzymania 100g wybranej soli
pliska
pustynnaróża
A] 2 Na + Cl2 => 2 NaCl M Na = 23 g M NaCl = 58,5 g m NaCl = 100 g 46 g Na ----------------- 117 g soli x Na ----------------------- 100 g x = 100 * 46 /117 =39,32g
b. Na20 + 2HCl => H20 + 2 NaCl M Na20 = 62 g m NaCl=100g M NaCl=58,5 g 62 g Na20 -------------------- 117 g soli x g Na20 ---------------------- 100 g x = 100*62/117 =53g c] NaOH + HCl => NaCl + H20 M NaOH = 40 g 40 g NaOH -------------------------- 58,5 g soli x g NAOH ------------------------ 100 g x = 100*40 / 58,5 = 68,37 g
M Na = 23 g
M NaCl = 58,5 g
m NaCl = 100 g
46 g Na ----------------- 117 g soli
x Na ----------------------- 100 g
x = 100 * 46 /117 =39,32g
b. Na20 + 2HCl => H20 + 2 NaCl
M Na20 = 62 g
m NaCl=100g
M NaCl=58,5 g
62 g Na20 -------------------- 117 g soli
x g Na20 ---------------------- 100 g
x = 100*62/117 =53g
c] NaOH + HCl => NaCl + H20
M NaOH = 40 g
40 g NaOH -------------------------- 58,5 g soli
x g NAOH ------------------------ 100 g
x = 100*40 / 58,5 = 68,37 g