Oblicz masę cząsteczkową związku :
Cu(No3)2
1mCu + 2mN + 6mO = (musisz spr masy w ukladzie SI) = 64u (unity) + 2*14u + 6*16u = 64 + 28 + 96u = 188u
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1mCu + 2mN + 6mO = (musisz spr masy w ukladzie SI) = 64u (unity) + 2*14u + 6*16u = 64 + 28 + 96u = 188u