Oblicz masę cząsteczkową podanych związków: Cu(NO3)2, FeSO4.Fe(NO3)2, MgSO4.
mCu(NO3)2=64u+2*14u+6*16u=64u+28u+96u=188u
mFeSO4=56u+32u+4*16u=88u+64u=132u
mFe(NO3)2=56u+2*14u+6*16u=56u+28u+96u=180u
mMgSO4=24u+32u+4*16u=56u+64u=120u
M Cu(NO₃)₂ = 64u + 2*(14u + 3*16u) = 188u
M FeSO₄ = 56u + 32u + 4*16u = 152u
M Fe(NO₃)₂ = 56u + 2*(14u + 3*16u) = 180u
M MgSO₄ = 24u + 32u + 4*16u = 120u
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
mCu(NO3)2=64u+2*14u+6*16u=64u+28u+96u=188u
mFeSO4=56u+32u+4*16u=88u+64u=132u
mFe(NO3)2=56u+2*14u+6*16u=56u+28u+96u=180u
mMgSO4=24u+32u+4*16u=56u+64u=120u
M Cu(NO₃)₂ = 64u + 2*(14u + 3*16u) = 188u
M FeSO₄ = 56u + 32u + 4*16u = 152u
M Fe(NO₃)₂ = 56u + 2*(14u + 3*16u) = 180u
M MgSO₄ = 24u + 32u + 4*16u = 120u