Oblicz masę cząsteczkową metanolu i podaj procent pierwiastków.
%H= ?
%C= ?
%O= ?
%H= 6u : 46u * 100%
%H= 13,04%
%C= 24u : 46u * 100% %C= 52,17%
%O= 16u : 46u * 100% %O= 34,78%
Metanol------>CH₃OH
mC=12u
mH=1u
mO=16u
mCH₃OH=12u+3*1u+16u+1u=12u+3u+16u+1u=32u
32u---------->100%
12u--------->x
x=37,5%<-------wegiel
32u----->100%
16u---->x
x=50%<------tlen
4u------>x
x=12,5%<-----wodór
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%H= 6u : 46u * 100%
%H= 13,04%
%C= 24u : 46u * 100%
%C= 52,17%
%O= 16u : 46u * 100%
%O= 34,78%
Metanol------>CH₃OH
mC=12u
mH=1u
mO=16u
mCH₃OH=12u+3*1u+16u+1u=12u+3u+16u+1u=32u
32u---------->100%
12u--------->x
x=37,5%<-------wegiel
32u----->100%
16u---->x
x=50%<------tlen
32u----->100%
4u------>x
x=12,5%<-----wodór