Question

Oblicz masę cząsteczkową dla szeregu homologicznego alkocholi ( metanol , etanol, propanol, butanol,pentanol)

Answer 1

Metanol CH3OH

mCH3OH=12u+4*1u+16u=32u

 

Etanol C2H5OH

mC2H5OH=2*12u+6*1u+16u=46u

 

Propanol C3H7OH

mC3H7OH=3*12u+8*1u+16u=60u

 

Butanol C4H9OH

mC4H9OH=4*12u+10*1u+16u=74u

 

Pentanol C5H11OH

mC5H11OH=5*12u+12*1u+16u=88u

Answer 2

Witam , 

 

C: 12u

H: 1u

O: 16u

 

I.  Metanol: CH₃OH

 

mCH₃OH: 12u+4u+16u=32u

 

II. Etanol: C₂H₅OH

 

mC₂H₅OH: 12u*2+6u+16u=46u

 

III. Propanol:  C₃H₇OH

 

mC₃H₇OH=12u*3+8u+16u=60u

 

IV: Butanol: C₄H₉OH

 

mC₄H₉OH=4*12u+10u+16u=74u

 

V. Pentanol C₅H₁₁OH

 

mC₅H₁₁OH=12*5u+12u+16u=88u