Oblicz masę 2 moli
a) Cu2O
b) 0,01 mola sacharozy ( C12H22O11)
podpunkt a mam zrobiony prosze tylko o zrobienie podpunktu b : )
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M C12H22O11=342g/mol
1mol C12H22O11------342g
2mole C12H22O11------xg
x = 684g
C12H22O11 - 12ux12+1ux22+16ux11=144u+22u+176u=342u
0,01mol - X
1mol - 342
x= 342x0,01= 3,42
0.01 - 3,42
2 mol - x
x= 3.42x2:0,01 = 684