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3 mole X moli
2 Mg + O2 = 2 MgO
2 mole 1 mol
proporcja: 2 mole - 1 mol
3 mole - X moli to X = 1,5 mola
A więc do spalenia 3 moli magnezu potrzeba 1,5 moli
2mole Mg - 1mol O₂
3mole Mg - xmoli O₂
x =1,5mola O₂
2 Mg + O2 = 2 MgO
2 mole 1 mol
3 mole-------- x
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x = 3 mole/2 = 1,5 mola O2
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