oblicz, krok po kroku. (n+2)•(2n - 2)=
(-n+2)•(n-2)=
(n-2)•(-2n-n)=
(2n-1)•(-2n+2)=
(-n-2)•(-n-2)=
(n+2)•(2n - 2)= 2n² - 2n + 4n - 4 = 2n² + 2n - 4
(-n+2)•(n-2)=2n - n² +2n - 4 = 4n - n² - 4
(n-2)•(-2n-n)= -2n² - n² + 4n + 2n = -3n² + 6n
(2n-1)•(-2n+2)= -4n² + 4n + 2n - 2 = -4n² + 6n - 2
(-n-2)•(-n-2)= n² + 2n + 2n + 4 = n² + 4n + 4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
(n+2)•(2n - 2)= 2n² - 2n + 4n - 4 = 2n² + 2n - 4
(-n+2)•(n-2)=2n - n² +2n - 4 = 4n - n² - 4
(n-2)•(-2n-n)= -2n² - n² + 4n + 2n = -3n² + 6n
(2n-1)•(-2n+2)= -4n² + 4n + 2n - 2 = -4n² + 6n - 2
(-n-2)•(-n-2)= n² + 2n + 2n + 4 = n² + 4n + 4