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2NaOH + H3PO4 -> Na2HPO4 + 2H2O
V NaOH = ?
Cm NaOH = 0,1mol/dm3
V H3PO4 = 200cm3 = 0,2dm3
Cm H3PO4 = 0,1mol/dm3
Cm = n/V
n = Cm*V
n = 0,2*0,1
n = 0,02 mola H3PO4 => 0,04mola NaOH (na jeden mol kwasu przypadają dwa mole zasady)
Cm = n/V
V = n/Cm
V = 0,04/0,1
V = 0,4dm3 NaOH