Oblicz indukcyjność cewki która przy częstotliwości 1000Hz ma reaktencje 2,5 kilo Ohma
f=1000 Hz
Xl=2,5kΩ=2500Ω
L=?
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Xl=2*π*f*L
L=Xl/(2*π*f)=2500Ω/(2*π*1000 1/s)=0,4H
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f=1000 Hz
Xl=2,5kΩ=2500Ω
L=?
------------------------------------------------------
Xl=2*π*f*L
L=Xl/(2*π*f)=2500Ω/(2*π*1000 1/s)=0,4H