Oblicz iloraz i wyznacz wzór ogólny podanego ciągu geometrycznego: a2= -27 a5= -8
a₂=-27
a₅=-8
a₅=a₁q⁴=a₂q³
-8=-27*q³
q³=8/27
q=2/3
an=a₁*(2/3)^(n-1)
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a₂=-27
a₅=-8
a₅=a₁q⁴=a₂q³
-8=-27*q³
q³=8/27
q=2/3
an=a₁*(2/3)^(n-1)