Odpowiedź:
a= 12 b = 13 c = 15
p = ( 12 + 13 + 15 ) : 2 = 40 : 2 = 20
p - a = 8 p - b = 7 p - c = 5
Pole z wzoru Herona
P = [tex]\sqrt{20*8*7*5} = \sqrt{5600} = \sqrt{4*14} *\sqrt{100} = 20\sqrt{14}[/tex]
Z wzoru
P = [tex]\frac{a*b*c}{ 4*R}[/tex] mamy [tex]20*\sqrt{14} = \frac{12*13*15}{4*R}[/tex] / * 4 *R
80[tex]\sqrt{14} *R = 12*13*15[/tex]
R = [tex]\frac{180*13}{80\sqrt{14} } = \frac{29,25}{\sqrt{14} } = \frac{29,25\sqrt{14} }{14}[/tex]
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Z wzoru P = p*r
mamy
r = P : p = [tex]\frac{20\sqrt{14} }{20} = \sqrt{14}[/tex]
---------------------------------
więc
r*R = [tex]\sqrt{14} *\frac{29,25\sqrt{14} }{14} = 29,25[/tex]
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Verified answer
Odpowiedź:
a= 12 b = 13 c = 15
p = ( 12 + 13 + 15 ) : 2 = 40 : 2 = 20
p - a = 8 p - b = 7 p - c = 5
Pole z wzoru Herona
P = [tex]\sqrt{20*8*7*5} = \sqrt{5600} = \sqrt{4*14} *\sqrt{100} = 20\sqrt{14}[/tex]
Z wzoru
P = [tex]\frac{a*b*c}{ 4*R}[/tex] mamy [tex]20*\sqrt{14} = \frac{12*13*15}{4*R}[/tex] / * 4 *R
80[tex]\sqrt{14} *R = 12*13*15[/tex]
R = [tex]\frac{180*13}{80\sqrt{14} } = \frac{29,25}{\sqrt{14} } = \frac{29,25\sqrt{14} }{14}[/tex]
----------------------------------------
Z wzoru P = p*r
mamy
r = P : p = [tex]\frac{20\sqrt{14} }{20} = \sqrt{14}[/tex]
---------------------------------
więc
r*R = [tex]\sqrt{14} *\frac{29,25\sqrt{14} }{14} = 29,25[/tex]
=============================
Szczegółowe wyjaśnienie: