Oblicz, ile gramów sodu oraz wody należy użyć, aby otrzymać 20g wodorotlenku sodu.
Obliczeń dokonaj na podstawie odpowiedniego równania reakcji chemicznej.
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2Na + 2H₂O ⇒ 2NaOH + H₂
M Na = 23g/mol
M H₂O = 2*1g/mol+16g/mol = 2g/mol+16g/mol = 18g/mol
M NaOH = 23g/mol+16g/mol+1g/mol = 40g/mol
do proporcji:
m Na = 23g/mol*2mol = 46g
m H₂O = 18g/mol*2mol = 36g
m NaOH = 40g/mol*2mol = 80g
46g Na ------------- 80g NaOH
x g Na -------------- 20g NaOH
80*x = 20*46 |:20
4x = 46 |:4
x = 11,5 [g]
36g H₂O ------------ 80g NaOH
y g H₂O ------------- 20g NaOH
80*y = 36*20 |:20
4y = 36 |:4
y = 9 [g]