oblicz ile g wapna (pierwiastka)znajduje się w 144g wapnia gaszonego?? pomocy na zaraz
Ca(OH)₂ - wapno gaszone
masa Ca(OH)₂: 40g + 2 * 16g + 2g = 74g
74g Ca(OH)₂ - 40g Ca
144g Ca(OH)₂ - x g Ca
x = (144g * 40g) : 74g ≈ 77,84g
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Ca(OH)₂ - wapno gaszone
masa Ca(OH)₂: 40g + 2 * 16g + 2g = 74g
74g Ca(OH)₂ - 40g Ca
144g Ca(OH)₂ - x g Ca
x = (144g * 40g) : 74g ≈ 77,84g