January 2019 1 46 Report
 \lim_{n \to \infty} a_n =( \frac{1}{6} - \frac{1}{12} + \frac{1}{24} - \frac{1}{48} +...+ \frac{1}{6} *(- \frac{1}{2} ) ^{n-1}

Oblicz granicę. Bardzo proszę!!
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.