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c = 3*10⁸m/s
Δm = Z*mprotonu + (A-Z)*mneutronu - mjądrowa
Δm= 2*1,672*10^-27kg + 2*1,675*10^-27kg - 4,0026*1,66*10^-27kg = 0,05*10^-27kg
Ewiązania = 0,05*10^-27kg*(3*10⁸m/s)² = 4,5*10^-12 J
Energia wiązania jądra helu wynosi 4,5*10^-12 J