Oblicz energię wiązania jądra He (góra 4 dół 2) . Masa protonu mp= 1,007 u, masa neutronu mn= 1,008 u u= 1,6610 do -27 kg Wynik podaj w dżulach i elektronowoltach
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mj = 4,001u
mp = 1,007u
mn = 1,008u
c² = 931,5MeV/u
Δm = (2*1,007+2*1,008) - 4,001
Δm = (2,014 + 2,016) - 4,001
Δm = 4,03 - 4,001 = 0,029u
Ew = Δmc² = 0,029*931,5 = 27,01MeV = 27,01*10⁶eV
Ew = 27,01*10⁶*1,6*10⁻¹⁹ = 43,21*10⁻¹³J