Oblicz długości odcinków o końcach:
a) A = (2,3) B = (6,6)
b) C = (-4, 1) D = (4, -3)
c) E = (-1, 2) F = (-3, - 4)
d) G = (3, -4) H = (-2, -4)
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Korzystając ze wzoru{
a)
b)
c)
d)
A[X₁;Y₁' B[ X₂;Y₂]
korzystam ze wzoru:
d=√[ (x₂-x₁)²+(y₂-y₁)²]
d=√[(6-2)²+(6-3)²]=√[16+9]=5
d=√[(4+4)²+(-3-1)²]=√[64+16]=√80=4√5
d=√[(-3+1)²+(-4-2)²]=√[4+36]=√40=2√10
d=√[(-2-3)²+(-4+4)²]=√25=5