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d=a√2
d=6√2
R=½*6√2=3√2
Odp. Promień okręgu opisanego na kwadracie o boku 6 wynosi 3√2
r=3√2
L=2πr
L=6√2π
r=a pierwiastka z 2 / 2
r=3√2
Obw=2πr
Obw=6pierwiastek z2π
pozdrawiam :)