oblicz deltę x2-3x+2=0
delta = b^2 - 4ac = 9-8= 1
x1=(3-1)/2 = 1
x2=(3+1)/2 = 2
a=1 b=-3 c=2
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delta = b^2 - 4ac = 9-8= 1
x1=(3-1)/2 = 1
x2=(3+1)/2 = 2
a=1 b=-3 c=2