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Fc=5000N/kg0
Odp.: na 0,5cm3 pada siła o wartosci 5000N/kg.
nie jestem tego pewna
F-sila = 500N
S-powierzchnia = 0.5cm²=0.000005m²
p=F/S p=[ N/m² = Pa] (paskal)
p= 500/0.000005=100000000Pa =100MPa
S=0,5cm² p=?
F=500N
p=F:S
p=500N:0,5cm²
p=500N : 0,005m²
p=100000Pa