Oblicz ciśnienie jakie panuje na powierzchni 0,5m2,jeżeli siła nacisku wynosi 1KN.?
P=Fn/S
Fn=1KN=1000N
S=0,5m2
P=1000N/0.5m2
P=2000Pa
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
P=Fn/S
Fn=1KN=1000N
S=0,5m2
P=1000N/0.5m2
P=2000Pa