Oblicz: a)pole kola o obwodzie 15pi cm b)obwod kola o polu 1,44pi cm^2
a)
L = 2πr
15π = 2πr
r = 7,5
P = πr²
P = π x (7,5)² = 56,25π [cm²]
b)
1,44π = πr²
r = 1,2
L = 2 x π x 1,2 = 2,4π [cm]
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a)
L = 2πr
15π = 2πr
r = 7,5
P = πr²
P = π x (7,5)² = 56,25π [cm²]
b)
P = πr²
1,44π = πr²
r = 1,2
L = 2πr
L = 2 x π x 1,2 = 2,4π [cm]
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)