Oblicz ale nie wiem o co chodzi bo nie mam treści 1. +2x+1=02. +2x-3=03. +5x+6=0
1. Tu chyba zamaist y powinien byś x i dla x licze równanie
x² + 2x + 1 = 0
(x + 1)² = 0
x + 1 = 0
x = -1
odp. x = 1
2.
x² + 2x - 3 = 0
a = 1, b = 2, c = -3
Δ = b² - 4ac = 4 + 12 = 16
√Δ = 4
x1 = (-b - √Δ) / 2a = (-2 - 4) / 2 = -6/2 = -3
x2 = (-b + √Δ) / 2a = (-2 + 4) / 2 = 2/2 = 1
odp. x = -3, x = 1
3.
x² + 5x + 6 = 0
a = 1, b = 5, c = 6
Δ = b² - 4ac = 25 - 24 = 1
√Δ = 1
x1 = (-5 - 1) / 2 = -6/2 = -3
x2 = (-5 + 1) / 2 = -4/2 = -2
odp. x = -3, x = -2
2) x² + 2x - 3 =0
Δ=b² - 4ac = 4 + 12 = 16
√Δ=4
x1=(-b-√Δ)/2a = (-2 - 4) / 2 = -6/2=-3
x2=(-b+√Δ)/2a = (-2+4)/2 = 2/2=1
3)
x²+5x+6=0
Δ=25 - 24 = 1
√Δ=1
x1=(-5-1)/2 = -6/2=-3
x2=(-5+1)/2 = -4/2 = -2
1) po konsultacji na pv, wiem ze powinien byc x² ,a nie y²
x²+2x+1=0
Δ=4-4=0
x=(-b)/2a = -2/2=-1
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
1. Tu chyba zamaist y powinien byś x i dla x licze równanie
x² + 2x + 1 = 0
(x + 1)² = 0
x + 1 = 0
x = -1
odp. x = 1
2.
x² + 2x - 3 = 0
a = 1, b = 2, c = -3
Δ = b² - 4ac = 4 + 12 = 16
√Δ = 4
x1 = (-b - √Δ) / 2a = (-2 - 4) / 2 = -6/2 = -3
x2 = (-b + √Δ) / 2a = (-2 + 4) / 2 = 2/2 = 1
odp. x = -3, x = 1
3.
x² + 5x + 6 = 0
a = 1, b = 5, c = 6
Δ = b² - 4ac = 25 - 24 = 1
√Δ = 1
x1 = (-5 - 1) / 2 = -6/2 = -3
x2 = (-5 + 1) / 2 = -4/2 = -2
odp. x = -3, x = -2
2) x² + 2x - 3 =0
Δ=b² - 4ac = 4 + 12 = 16
√Δ=4
x1=(-b-√Δ)/2a = (-2 - 4) / 2 = -6/2=-3
x2=(-b+√Δ)/2a = (-2+4)/2 = 2/2=1
3)
x²+5x+6=0
Δ=25 - 24 = 1
√Δ=1
x1=(-5-1)/2 = -6/2=-3
x2=(-5+1)/2 = -4/2 = -2
1) po konsultacji na pv, wiem ze powinien byc x² ,a nie y²
x²+2x+1=0
Δ=4-4=0
x=(-b)/2a = -2/2=-1