Oblicz a1 i a10 oraz sumę s10 ciągu arytmetycznego jesli dane sa a4=8 i a 8=20
a1+3r=8
a1+7r=20
a1+3r+4r=20
8+4r=20
4r=12
r=3
a1+9=8
a1=-1
a10=a1+9r=26
a10=-1+27=26
s10=-1+26/2 razy 10=125
a4 = a1+3r = 8
a8 = a1+7r = 20
-4r=-12
r= 3
a1+9 =8
a1 = -1
a10 = a1+9r = -1+ 9*3 = 26
S10 = (-1+26)/2 * 10 = 12,5 *10=125
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a1+3r=8
a1+7r=20
a1+3r+4r=20
8+4r=20
4r=12
r=3
a1+9=8
a1=-1
a10=a1+9r=26
a10=-1+27=26
s10=-1+26/2 razy 10=125
a4 = a1+3r = 8
a8 = a1+7r = 20
-4r=-12
r= 3
a1+9 =8
a1 = -1
a10 = a1+9r = -1+ 9*3 = 26
S10 = (-1+26)/2 * 10 = 12,5 *10=125