promil to 1/1000, wobec czego:
a) 3*1/1000*1500 = 4.5 [kg]
b) 7*1/1000*20000 = 140 [zł]
c) 1.5*1/1000*4000 = 6 [kg] = 0.006 [t]
Zadanie:
t1 - podatki Artura
t2 - podatki Piotra
r - różnica
r = (t2-t1)*19% = (2500 - 1500)*0.19 = 1000*0.19 = 190 [zł]
a) 3*1/1000*1500kg = 4.5 kg
b) 7*1/1000*20000zł = 140zł
c) 1.5*1/1000*4000kg = 6kg = 0.006t
p1 - podatki Artura
p2 - podatki Piotra
r = (p2-p1)*19% = (2500 - 1500)*0.19 = 1000*0.19 = 190zł
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promil to 1/1000, wobec czego:
a) 3*1/1000*1500 = 4.5 [kg]
b) 7*1/1000*20000 = 140 [zł]
c) 1.5*1/1000*4000 = 6 [kg] = 0.006 [t]
Zadanie:
t1 - podatki Artura
t2 - podatki Piotra
r - różnica
r = (t2-t1)*19% = (2500 - 1500)*0.19 = 1000*0.19 = 190 [zł]
a) 3*1/1000*1500kg = 4.5 kg
b) 7*1/1000*20000zł = 140zł
c) 1.5*1/1000*4000kg = 6kg = 0.006t
Zadanie:
p1 - podatki Artura
p2 - podatki Piotra
r - różnica
r = (p2-p1)*19% = (2500 - 1500)*0.19 = 1000*0.19 = 190zł