Question

Obl pole powierzchni i obj ostrosłupa prawidłowego

Answer 1

A=8
b=6
Pc=Pp+3*1/2 ah
Pp=a²√3/4
Pp=8*8√3/4 =8*2√3
Pp=16√3
h²=b²-(1/2 a)²
h²=6²-4² =36-16 =20 =4*5
h=√(4*5)
h=2√5
Pc=16√3 +3*8*2√5/2
Pc=16√3+24√5
Pc=8(2√3+3√50 [j²]
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V=1/3 Pp*H
h1        wysokośc podstawy
H²=b² -(2/3 h1)²
h1=a√3/2
2/3 h1= a√3/3 =8√3/3
H²=6² -(8√3/3) =36 -64*3/9 =108/3 -64/3 =44/3
H=√44/√3 =√(44*3)/3 =√(4*33)/3
H=2√33/3
V=16√3*2√33/(3*3)
V=32√99/9
V=32*3√11/9
V=32√11/3 [j³]