Question

obicz.:

a)1⁷₈ × (-6) =

b)-1¹₅ × 2¹₂=

c)-1³₄ : 8=

d)1¹₃ × 0,5=

e)5,25 : (-1¹₂)=

f)-1,5 : (-2¹₃)=

g)-1³₄ + 7¹₅=

h) -2³₈ - ¹₁₂ =

i)-13,1-2,5=

j)17.21-20,03=

k)-0,82 × (-0,3)=

l)-0,75 -(1²₃)=

np 1⁶₅ to ułamek jesli ktos nie wie..;p

prosze o rozwiazanie..chociaz polowe :)

Answer 1

a)1⁷₈ × (-6) =
= 15/8 * (-6) =
= -45/4 =
= -11 i  1/4

b)-1¹₅ × 2¹₂ =
= - 6/5 * 5/2 =
= -3

c)-1³₄ : 8 =
= -7/4 * 1/8 =
= - 7/32

d)1¹₃ × 0,5 =
= 4/3 * 1/2 =
= 2/3

e)5,25 : (-1¹₂) =
= 5 1/4 : (-3/2) =
= 21/4 * (-2/3) =
= 7/2 =
= 3,5

f)-1,5 : (-2¹₃) =
= -15/10 : (-7/3) =
= -15/10 * (-3/7) =
= 45/70 =
= 9/14

g)-1³₄ + 7¹₅ =
= - 7/4 + 36/5 =
= - 35/20 + 144/20 =
= 109/20 =
= 5 i 9/20

h) -2³₈ - ¹₁₂ =
= -19/8 - 1/12 =
= -57/24 - 2/24 =
= -59/24 =
= - 2 11/24

i)-13,1-2,5 =
= -15,6

j)17.21-20,03 =
= -2,82

k)-0,82 × (-0,3) =
= 0,246

l)-0,75 -(1²₃) =
= -3/4 - 5/3 =
= - 9/12 - 20/12 =
= -29/12
= -2 i 5/12