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pH NaOH
[OH^-] = 0,01 mol/dm3 = 10^-2 mol/dm3
pOH = -lg 10^-2
pOH = 2
pOH + pH = 14
pH = 14 – pOH
pH = 14 – 2 = 12 – pH NaOH
pH wody = 7
pH wody zwiększy się o 12 – 7 = 5
pH wody zwiekszy sie o 5 jednostek.