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dl. okręgu opisanego 2π * 4 = 8π
różnica 8π - 4π√3 = 4π( 2 - √3)
R=a
L=2πr
L=2π*4=8π=25
Okrąg wpisany
r=a√3/2
r=4√3/2=2√3
L=2πr
L=2π*2√3=4π√3=22
25-22=3
dlugosc opisanego---> 2πr 8π
dlugosc wpisanego---> 2πr 4√3π
8π-4√3π=4√3π