Penjelasan dengan langkah-langkah:
5.
a. Panjang BC
BC = AD
BC = 13 cm
b. Panjang AE
AE = (AB - DC) ÷ 2
AE = (21 - 11) ÷ 2
AE = 5 cm
c. Panjang DE
DE = √(AD² - AE²) = √(13² -5²) = √(169 - 25) = √144 = 12 cm
d. Besar ∠DAB
∠DAB = ∠CBA
∠DAB = 42°
e. Besar ∠BCD
∠BCD + ∠CBA = 180°
∠BCD + 42° = 180°
∠BCD = 180° - 42°
∠BCD = 138°
6.
a. Keliling :
AB + BC + CD + DA
21 + 13 + 11 + 13
58 cm
b. Luas
(AB + CD)/2 × DE
(21 + 11)/2 × 12
16 × 12
192 cm²
7.
BC = 2x + 5
13 = 2x + 5
13 - 5 = 2x
8 = 2x
8/2 = x
4 = x
8.
a. Besar ∠BCD
∠BCD + 48° = 180°
∠BCD = 180° - 48°
∠BCD = 132°
b. Panjang sisi BC
BC = √CP² + PB² = √15² + (21 - 13)² = √225 + 64 = √289 = 17 cm
c. Keliling Trapesium
21 + 17 + 13 + 15
66 cm
d. Luas Trapesium
(AB + CD)/2 × DA
(21 + 13)/2 × 14
238 cm²
Mohon maaf kalau salah tolong dikoreksi. Semoga bermanfaat ^-^
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Penjelasan dengan langkah-langkah:
5.
a. Panjang BC
BC = AD
BC = 13 cm
b. Panjang AE
AE = (AB - DC) ÷ 2
AE = (21 - 11) ÷ 2
AE = 5 cm
c. Panjang DE
DE = √(AD² - AE²) = √(13² -5²) = √(169 - 25) = √144 = 12 cm
d. Besar ∠DAB
∠DAB = ∠CBA
∠DAB = 42°
e. Besar ∠BCD
∠BCD + ∠CBA = 180°
∠BCD + 42° = 180°
∠BCD = 180° - 42°
∠BCD = 138°
6.
a. Keliling :
AB + BC + CD + DA
21 + 13 + 11 + 13
58 cm
b. Luas
(AB + CD)/2 × DE
(21 + 11)/2 × 12
16 × 12
192 cm²
7.
BC = 2x + 5
13 = 2x + 5
13 - 5 = 2x
8 = 2x
8/2 = x
4 = x
8.
a. Besar ∠BCD
∠BCD + ∠CBA = 180°
∠BCD + 48° = 180°
∠BCD = 180° - 48°
∠BCD = 132°
b. Panjang sisi BC
BC = √CP² + PB² = √15² + (21 - 13)² = √225 + 64 = √289 = 17 cm
c. Keliling Trapesium
AB + BC + CD + DA
21 + 17 + 13 + 15
66 cm
d. Luas Trapesium
(AB + CD)/2 × DA
(21 + 13)/2 × 14
238 cm²
Mohon maaf kalau salah tolong dikoreksi. Semoga bermanfaat ^-^