Question

Nomor 7 saja. Terima kasih

Answer 1

Verified answer

FLUIDA DINAMIS
•

H = 4 m
h₁ = 1,8 m
g = 9,8 m/s²
A = 2,8 cm² = 2,8×10⁻⁴ m²

h₂ = H - h₁
h₂ = 4 - 1,8 = 2,2 m

a][ laju pancaran air
v = √(2 g h₁)
v = √(2 • 10 • 1,8)
v = 6 m/s ✓

b][ debit
Q = A v
Q = 2,8×10⁻⁴ • 6
Q = 1,68×10⁻³ m³/s ✓

c][ jarak pancar horizontal
x = 2 √(h₁ • h₂)
x = 2 √(1,8 • 2,2)
x ≈ 3,98 m ✓