Question

Nomor 5 pake cara yaa.....

Answer 1

Rumus cosinus
PR² = RQ² + PQ² - 2 RQ PQ cos Q
cos Q = (RQ² + PQ² - PR²)/(2 RQ PQ)
=(13² + 15² - 8²)/(2.13.15)
=11/13

misal O terletak di antara PQ sehingga PO=x cm dan OQ=(15-x) cm
cos Q=OQ/RQ
11/13=(15-x)/13
15-x=11
x=4
OQ=11 cm

Pytaghoras
RO²=RQ²-OQ²
=169-121
=48
RO=√48
=4√3 cm

sin Q=RO/RQ
=(4√3)/13
=4/13 √13