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QR = 12
π = 3,14
D² = PQ²+QR²
= 16²+12²
=256+144
D² = 400
D = √400 = 20
r = 20:2 = 10
l.lingkaran-luas persegi =
(πxr²) - (pxl) =
(3,14x10²) - (16x12)=
314 - 192 = 122
mf ya
a = QR
= 12 cm
b = PQ
= 16 cm
a² + b² = c²
12² + 16² = c²
144 + 256 = c²
400 = c²
√400 = √c²
20 = c
Jadi panjang diagonal = diameter adalah 20 cm.
L lingkaran = 1/4 × π × d²
= 1/4 × 3,14 × 20²
= 1/4 × 3,14 × 400
= 3,14 × 100
= 314 cm²
L persegi panjang = p × l
= 16 cm × 12 cm
= 192 cm²
L yg diarsir = L lingkaran - L persegi panjang
= 314 cm² - 192 cm²
= 112 cm²
Jadi jawabannya adalah yang a. 112 cm²