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= 1600.37,1
= 59,36 kJ
Mr = C₂H₅OH; (Ar C = 12, Ar H = 1, Ar O = 16)
= 46
mol etanol (n) = m/Mr
= 2/46
= 1/23 mol
ΔH = Q/n
= 59,36 kJ/(1/23 mol)
= 1365,28 kJ/mol (karena melepas kalor, maka ΔH negatif)
= -1365,28 kJ/mol