Question

Nomor 1......m..mmm..........

Answer 1

Jawaban dilampirkan difoto....

Answer 2

*Cara Mudahnya adalah mengakarkan dahulu sebelum memangkatkan nya.
*Sifat penjumlahan pengurangan Akar
→ a√b + c√b = (a + c)√b
→ √a² = a
→ a^(-1) = 1 / a¹
→ a^(1/b) = ^b√a

1. a. {^5√(32)^4} × {3³} × {^4√(16)^(-7)}
= 2^(4) × 3³ × 2^(-7)
= 16 × 27 × 1/{2^(7)}
= 432 × 1/128
= 432 ÷ 128
= 432/128
= 216/64 = 108/32 = 54/16 = 27/4 √

1.b. 2√(20) + √(28) - 3√(125) + 4√(63) - 5√(80)
= 2√(4 × 5) + √(4 × 7) - 3√(25 × 5) + 4√(9 × 7) - 5√(16 × 5)
= (2×2)√(5) + 2√7 - (3×5)√(5) + (4×3)√(7) - (5×4)√(5)
= 4√5 + 2√7 - 15√5 + 12√7 - 20√5
= (4 - 15 - 20)√5 + (2 + 12)√7
= -31√5 + 14√7
= 14√7 - 31√5

Semoga Membantu :)