2) diket: r = 1 m = 10 dm t = 1 m = 10 dm a) volume bak = πr²t = 3,14 x 10 x 10 x 10 = 3140 dm³ = 3140 liter b) 1/2 menit terisi 1/2 liter, maka 1 menit terisi 1 liter --> debit = 1 liter/menit waktu smpai penuh = volume / debit = 3140/1 = 3140 menit = 52 jam 20 menit
3a) mean = (5+2.6+3.7+2.8+2.9)/10 = 72/10 = 7,2 b) modus = 7 c) 5,6,6,7,7,7,8,8,9,9 --> median = data ke 10/2 = 5,5 yaitu (7+7)/2 = 7
4 pelemparan 2 mata uang --> n(S) = 4 a) muncul 2 gambar = {GG} --> n(A) = 1 P(2G) = 1/4 b) tidak muncul angka = muncul keduanya gambar penyelesaian sama dgn atas ya.. c) muncul muka sama = {AA,GG} --> n(A) = 2 P(A) = 2/4 = 1/2
5) pelemparan 3 mata uang --> n(S) = 8 a) muncul paling sedikit 1 muka uang?? mgkin 1 muka angka ya.. :) muncul paling sedikit 1 muka angka : -1A,2G = {AGG,GAG,GGA} -2A,1G = {AAG,AGA,GAA} -3A = {AAA} n(A) = 7 P(A) = 7/8 F h (A) = P(A) x n = 7/8 x 120 = 105 kali b) muncul 2angka 1 gambar = {AAG,AGA,GAA} --> n(A) = 3 P(A) = 3/8 F h (A) = 3/8 X 120 = 45 kali
2) diket: r = 1 m = 10 dm
t = 1 m = 10 dm
a) volume bak = πr²t = 3,14 x 10 x 10 x 10 = 3140 dm³ = 3140 liter
b) 1/2 menit terisi 1/2 liter, maka 1 menit terisi 1 liter --> debit = 1 liter/menit
waktu smpai penuh = volume / debit
= 3140/1
= 3140 menit
= 52 jam 20 menit
3a) mean = (5+2.6+3.7+2.8+2.9)/10 = 72/10 = 7,2
b) modus = 7
c) 5,6,6,7,7,7,8,8,9,9 --> median = data ke 10/2 = 5,5 yaitu (7+7)/2 = 7
4 pelemparan 2 mata uang --> n(S) = 4
a) muncul 2 gambar = {GG} --> n(A) = 1
P(2G) = 1/4
b) tidak muncul angka = muncul keduanya gambar
penyelesaian sama dgn atas ya..
c) muncul muka sama = {AA,GG} --> n(A) = 2
P(A) = 2/4 = 1/2
5) pelemparan 3 mata uang --> n(S) = 8
a) muncul paling sedikit 1 muka uang?? mgkin 1 muka angka ya.. :)
muncul paling sedikit 1 muka angka :
-1A,2G = {AGG,GAG,GGA}
-2A,1G = {AAG,AGA,GAA}
-3A = {AAA}
n(A) = 7
P(A) = 7/8
F h (A) = P(A) x n = 7/8 x 120 = 105 kali
b) muncul 2angka 1 gambar = {AAG,AGA,GAA} --> n(A) = 3
P(A) = 3/8
F h (A) = 3/8 X 120 = 45 kali
semoga membantu ya :)