Question

Nomor 1 a&b pliss, thanks before guys :)

Answer 1

1/(1/cosα - sinα/cosα) - 1/(1/cosα + snα/cosα)
= cosα/ (1-sinα) - cosα/(1 + sinα)
= Cosα + sinαcosα - (cosα - sinαcosα)
                1 - sin²α
= 2sinαcosα
      cos²α
= 2sinα/cosα
 = 2 Tanα

Mudah-mudahan membantu dan jadikan saya yang terbaik :)