(u / v)' = u' v - v' u / v^2
u = 2x - 3
u' = 2
v = √x - 2
v' = 1 / 2√x
u' v - v' u = 2 (√x - 2) - (1 / 2√x) (2x - 3)
ganti x = 9
2 (√9 - 2) - (1 / 2 √9) (2 (9) - 3)
2 - (1/6 * 15) = -3/6 = -1/2
v^2 = (√x - 2)^2 = x - 4 √x + 4
v^2 = 9 - 12 + 4 = 1
jadi g' (9) = -1/2
Jadi , jawabannya C. -1/2
Materi Turunan Fungsi Aljabar : brainly.co.id/tugas/22813861
Kelas : 11 SMA
Mapel : Matematika
Kategori : Turunan Fungsi Aljabar
Kode : 11.2.9
Kata Kunci : turunan fungsi
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Verified answer
Pembahasan
(u / v)' = u' v - v' u / v^2
u = 2x - 3
u' = 2
v = √x - 2
v' = 1 / 2√x
u' v - v' u = 2 (√x - 2) - (1 / 2√x) (2x - 3)
ganti x = 9
2 (√9 - 2) - (1 / 2 √9) (2 (9) - 3)
2 - (1/6 * 15) = -3/6 = -1/2
v^2 = (√x - 2)^2 = x - 4 √x + 4
ganti x = 9
v^2 = 9 - 12 + 4 = 1
jadi g' (9) = -1/2
Kesimpulan
Jadi , jawabannya C. -1/2
Pelajari lebih lanjut
Materi Turunan Fungsi Aljabar : brainly.co.id/tugas/22813861
Detail Jawaban
Kelas : 11 SMA
Mapel : Matematika
Kategori : Turunan Fungsi Aljabar
Kode : 11.2.9
Kata Kunci : turunan fungsi