ImmanuelSinaga(7) (x+1)² - 5(x+1) + 6 > 0 misalkan x + 1 = a a² - 5a + 6 > 0 faktorkan (a - 3)(a - 2) > 0 a = 3 a = 2 x + 1 = 3 x + 1 = 2 Batas : x = 2 x = 1 cobakkan x > 2 = positif x < 1 = positif Maka x > 2 dan x<1 ===> B.
(8) (x-3)/(x+4) ≥ 0 x ≠ -4 x = 3 cobakkan : x ≥ 3 = positif x < -4 = postif Maka -4 > x ≥ 3 ===> B.
0 votes Thanks 1
hilmy98
kok pinter bgt seh aku gk kepikiran pake cara itu
(x+1)² - 5(x+1) + 6 > 0
misalkan x + 1 = a
a² - 5a + 6 > 0
faktorkan
(a - 3)(a - 2) > 0
a = 3 a = 2
x + 1 = 3 x + 1 = 2
Batas : x = 2 x = 1
cobakkan
x > 2 = positif
x < 1 = positif
Maka x > 2 dan x<1 ===> B.
(8)
(x-3)/(x+4) ≥ 0
x ≠ -4
x = 3
cobakkan :
x ≥ 3 = positif
x < -4 = postif
Maka -4 > x ≥ 3 ===> B.