No. 5nya please butuh banget cara jalannya!!! #makasih
agungizzulhaq1
(sin x + 1)(sin x + 2) = cos² x sin² x + 2sin x + sin x + 2 = 1 - sin^2 x sin² x + 3sin x + 2 = 1 - sin² x sin² x + sin² x + 3sin x + 2-1 = 0 2sin² x + 3sin x + 1 =0 (2sin x + 1)(sin x + 1) = 0 sin x = -0,5 atau sin x = -1 sin x = sin 210° atau sin x = sin 270°
uji # x = β + k 360° x = 210° + k 360°
k = -1 x = 210 - 360 x = -150 (Tidak memenuhi)
k = 0 x = 210 + 0.360 x = 210
k = 1 x = 210 + 360 x = 570 (tidak memenuhi)
#x = (β-180)° + k 360° x = (210 - 180)° + k 360° x = 30° + k 360°
k = -1 x = 30 - 360 x = -330 (Tidak memenuhi
k = 0 x = 30 + 0 x = 30
k = 1 x = 30 + 360 x = 390 ( Tidak memenuhi)
#x = β + k 360 x = 270 + k 360
k = 0 x = 270
#x = (β-180) + k 360 x = (270 - 180) + k 360 x = 90 + k 360
sin² x + 2sin x + sin x + 2 = 1 - sin^2 x
sin² x + 3sin x + 2 = 1 - sin² x
sin² x + sin² x + 3sin x + 2-1 = 0
2sin² x + 3sin x + 1 =0
(2sin x + 1)(sin x + 1) = 0
sin x = -0,5 atau sin x = -1
sin x = sin 210° atau sin x = sin 270°
uji
# x = β + k 360°
x = 210° + k 360°
k = -1
x = 210 - 360
x = -150 (Tidak memenuhi)
k = 0
x = 210 + 0.360
x = 210
k = 1
x = 210 + 360
x = 570 (tidak memenuhi)
#x = (β-180)° + k 360°
x = (210 - 180)° + k 360°
x = 30° + k 360°
k = -1
x = 30 - 360
x = -330 (Tidak memenuhi
k = 0
x = 30 + 0
x = 30
k = 1
x = 30 + 360
x = 390 ( Tidak memenuhi)
#x = β + k 360
x = 270 + k 360
k = 0
x = 270
#x = (β-180) + k 360
x = (270 - 180) + k 360
x = 90 + k 360
k = 0
x = 90
HP {30°, 90°, 210°,270°}