Question

No. 5 bgmn???---------

Answer 1

Log 2 = a dan log 3 = b
2^(x + 1) = 3^(2 - 3x) kedua ruas di log kan
=> log 2^(x + 1) = log 3^(2 - 3x)
=> (x + 1) log 2 = (2 - 3x) log 3
=> (x + 1).a = (2 - 3x) . b
=> ax + a = 2b - 3bx
=> ax + 3bx = 2b - a
=> x(a + 3b) = 2b - a
=> x = (2b - a) / (a + 3b)
maka x + 2
= (2b - a)/(a + 3b) + 2 . (a + 3b)/(a + 3b)
= (2b - a)/(a + 3b) + (2a + 6b)/(a + 3b)
= (a + 8b)/(a + 3b)