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√12² + 5²
= √144 + 25
= √169
= 13 cm
d = 13
r = 13/2 cm
luas setengah lingkaran besar = 1/2πr²
= 1/2 . 3,14 . (13/2)²
= 1,57 . 169/4
= 66,3325 cm²
luas segitiga = 1/2at
= 1/2.5.12
= 5.6
= 30 cm²
irisan = 66,3325 - 30
= 36,3325
luas setengah lingkaran sedang = 1/2πr²
= 1/2 . 3,14 . 6²
= 1,57 . 36
= 56,52 cm²
luas setengah lingkaran kecil = 1/2πr²
= 1/2 . 3,14 . (5/2)²
= 1,57 . 25/4
= 9,8125 cm²
jumlah = 56,52 + 9,8125
= 66,3325 cm²
Luas daerah yang diarsir = 66,3325 - 36,3325
= 30 cm²