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a = 2 m/s²
t₂ = 20 s
ditanya : a) v = ... ?
b) x = .... ?
dijawab :
disini terdapat 2 peristiwa yaitu GLBB (peristiwa awal / 15 sekon pertama)dan GLB (20 sekon selanjutnya)
a) v = at₁
= 2 . 15
v = 30 m/s
b) x = x₁ + x₂
= (1/2 a t₁²) + (v . t₂)
= (1/2 . 2 . 15²) + (30 . 20)
= 225 + 600
x = 825 m