Question

No 34 Tolong ya dijawab.
Pakai caranya, pliss.
makasih

Answer 1

Nilai r = 1
karena itu tripel phytagoras yaitu:
PQ=3
QR=4
RP=5

Answer 2

(3r+1)^2 + (2+r)^2 = 5^2
9r^2 +6r + 1 + 4 + 4r + r^2 = 25
10r^2 + 10r + 5 = 25
10r^2 + 10r + 5 - 25 = 0
10r^2 + 10r - 20 = 0
r^2 + r - 2 = 0
(r - 1) (r + 2) = 0
(r - 1) = 0
r = 1
atau
(r + 2) = 0
r = -2
nilai r yg memenuhi yaitu r = 1