Question

No 28 digambar! pakai cara dan jawab tidak asal yaaa

Answer 1

Verified answer

Volume kerucut = 1/3 × phi × r^2 × t
18.480 = 1/3 × 22/7 × r^2 × 10
18.480 = 22/21 × r^2 × 10
18.480 × 21/22 = r^2 × 10
17.640 = r^2 × 10
@ r^2 = 17.640/10
@ r^2 = 1.764
@ r = 42

S :
@ s = / r^2 + t^2
@ s = / (42)^2 + (10)^2
@ s = / 1764 + 100
@ s = / 1864
@ s = 43,17

Luas selimut kerucut (lss) = phi × r × s
@ 22/7 × 42 × 43,17
@ 5.698,98 cm^3


Semoga membantu.. ^_^