Question

No 23&24 gimana ya caranya??

Answer 1

Verified answer

FENOMENA KUANTUM
▷Energi Foton

23.]
E = 3,5 eV = 3,5 (1,6 × 10⁻¹⁹)= 5,6 × 10⁻¹⁹ J
h = 6,63 × 10⁻³⁴ Js ... tetapan Planck

f = ???

E = h f
f = E / h
f = (5,6 × 10⁻¹⁹ J) / (6,63 × 10⁻³⁴ Js)
f ≈ 8,45 × 10¹⁴ Hz [A]

24.]
λ = 525 nm = 525 × 10⁻⁹ m
n = 3
h = 6,63 × 10⁻³⁴ Js
c = 3 × 10⁸ m/s ... kec. cahaya

E = ???

E = n h c / λ
E = 3 × (6,63 × 10⁻³⁴ Js) × (3 × 10⁸ m/s) / (525 × 10⁻⁹ m)
E ≈ 1,14 × 10⁻¹⁸ J

Jika dikonversi ke satuan elektron Volt :
E ≈ (1,14 × 10⁻¹⁸) / (1,6 × 10⁻¹⁹)
E = 7,125 eV [C]