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Verified answer
Nomor 3.E = kq / r²
q = Er² / k
= (1,2 N/C)(0,3 m)² / (9 × 10⁹ Nm²/C²)
= 1,2 × 10⁻¹¹ C
Nomor 2
F = kq₁q₂ / r²
r = √(kq₁q₂ / F)
= √[(9 × 10⁹ Nm²/C²)(15 C)(3 C) / (2,5 N)]
= √(0,162 × 10¹² m²)
= 9/50 √5 × 10⁻⁶ m
= 9/50 √5 μm