Question

No 1,2 plus cara.
di jaeab ya....

Answer 1

1 . Luas penutup
= 1/2 × 5 cm × 12 cm × 2
= × 60 cm² × 2
= 60 cm²

luas sisi
= (20 cm × 12 cm) + (20 cm × 5 cm) + (20 cm × 13 cm)
= 240 cm² + 100 cm² + 260 cm²
= 600 cm²

Luas permukaan
= 60 cm² + 600 cm²
= 660 cm²

2. FE
= √(AE - BF)² + AB²
= √(8-5)² + 4²
= √9+16 =√25 = 5 cm

Luas permukaan
     = 2 Luas alas +  tinggi (Keliling alas)
     = 2 (AE+BF) AB + BC (AB + BF + FE + AE)
     = (8+5) 4 + 6 (4+5+5 +8)
     = 13 x 4 + 6 x 22
     = 52 + 132
     = 184 cm²